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Design
of Atmospheric Storage Tanks by API Std 650
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Calculation
of Thicknesses by The Variable-Design-Point Method (5.6.4)
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Tables y Standards
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-
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API Std 650 Welded Tanks for oil Storage, para.
5.6.4
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-
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Minimum Plate Thickness by API Std 650 (5.6.1.1)
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-
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Plate Thickness by ASME / ASTM
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-
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Tables 5-2a and 5-2b Allowable stress for design
& Hydrostatic Test conditions
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VARIABLE-DESIGN-POINT
METHOD
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(Enter values in yellow cells for calculations)
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DATA INPUT
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Capacity (Barrels)
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m³
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G (Fluid Specific Gravity)
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Fluid Density, r (g/cm³) (1)
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Note (1):
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(Consider r ≥ 1 g/cm³
for the Hmáx calculation)
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Ground Resistance, Ps (Kg/cm²)
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Outage (m) (2)
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Note (2):
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(Distance from the maximum level to the upper edge)
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Course
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Plate
Specification
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Plate Width, E (m)
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Hydrostatic Test Stress, St (Mpa)
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Product Design Stress, Sd (Mpa)
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Corrosion Allowance, CA (mm)
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Hmáx = 1000*Ps/ρ
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cm =
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m
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Htank ≤ Hmáx
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m
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h = Htank-outage
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m
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D = (V 4/πh)⁰∙⁵
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m =
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m³ =
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barrels
|
According to
API Std 650
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Dtank
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m =
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m³ =
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barrels
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No. of Courses = Htank/E
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OUTPUT tmin & SELECTION tuse
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Courses
|
Design
Condition td
(mm)
|
Hidrostatic
Test Condition tt
(mm)
|
tmin
(mm)
|
tuse (*)
(mm)
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t1
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t2
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t3
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t4
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t5
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t6
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t7
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t8
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Notes:
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- Dimensions in mm
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- (*) Verified Minimum Thickness by API Std 650
(5.6.1.1)
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|
CALCULATING
THE THICKNESS OF THE 1ST
SHELL COURSE (N=1)
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N
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H = Htank - (N-1)E
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m
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|
DESIGN
CONDITIONS
|
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|
|
tpd
=
|
4.9D(H-0.3)G
|
+ CA
|
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|
mm
|
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Sd
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|
t1d
=
|
[
|
1.06 -
|
0.0696D
|
(
|
HG
|
)
|
0,5
|
]
|
(
|
4.9HDG
|
)
|
+ CA
|
|
mm
|
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|
H
|
Sd
|
|
Sd
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|
t1d need
not be greater than tpd
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Lower between tpd y t1d
|
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|
HYDROSTATIC
TEST CONDITIONS
|
|
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|
|
tpt =
|
4.9D(H-0.3)
|
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|
mm
|
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St
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|
t1t =
|
[
|
1.06 -
|
0.0696D
|
(
|
H
|
)
|
0,5
|
]
|
(
|
4.9HD
|
)
|
|
|
mm
|
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|
H
|
St
|
|
St
|
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|
|
t1t
need not be greater than tpt
|
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|
Lower between tpt y t1t
|
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|
|
|
|
|
THICKNESS
OF THE FIRST COURSE
|
|
|
|
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|
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|
|
|
Higher between t1d y t1t
(t1min)
|
|
|
|
|
mm
|
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|
|
t1use
|
|
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|
mm
|
t1use> t1min
|
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|
|
Verify L/H ≤ 1000/6
|
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|
t = t1use - CA
|
|
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|
mm
|
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|
L = (500 D t)⁰∙⁵
|
|
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|
H = Htank - (N-1)E
|
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|
L/H =
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|
|
CALCULATING THE THICKNESS OF THE 2ND SHELL COURSE (N=2)
|
|
|
|
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|
|
UPPER-COURSE METHOD FOR DESIGN CONDITIONS (t2a = tdx-CA)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t1
= t1use - CA
|
|
|
|
|
|
|
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|
|
mm
|
|
|
|
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|
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|
|
h1
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
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|
|
|
|
|
R =
|
h1
|
|
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|
|
|
|
|
(r t1)⁰∙⁵
|
|
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|
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|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
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|
|
|
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|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
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|
|
How R =
|
|
→
|
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|
|
|
|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h1
|
|
mm
|
h1
|
|
mm
|
h1
|
|
mm
|
h1
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
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m
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H (Analysis)
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m
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G
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G
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G
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G
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Sd
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MPa
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Sd
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MPa
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Sd
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MPa
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Sd
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MPa
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CA
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mm
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CA
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mm
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CA
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mm
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CA
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mm
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t1d = t1use
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mm
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t1d = t1use
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mm
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t1d = t1use
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mm
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t1d = t1use
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mm
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tpd - CA=
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4.9D(H-0.3)G
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mm
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tdx-CA
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mm
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tdx1-CA
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mm
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tdx2-CA
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mm
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Sd
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tL = t1use - CA
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mm
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tL = t1use-CA
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mm
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tL = t1use-CA
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mm
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tL = t1use-CA
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mm
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tu
= tpd-CA
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mm
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tu = tdx-CA
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mm
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tu = tdx1-CA
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mm
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tu = tdx2-CA
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mm
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K = tL/tu
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K
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K
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K
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
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C
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C
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X₁ = 0.61(rtu)⁰∙⁵+(320CH)
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X₁
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X₁
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X₁
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X₂ = 1000CH
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X₂
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X₂
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X₂
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X₃ = 1.22(rtu)⁰∙⁵
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X₃
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X₃
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X₃
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X
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X
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X
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X
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tdx - CA=
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4.9D(H-X/1000)G
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mm
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tdx1-CA
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mm
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tdx2-CA
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mm
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tdx3-CA
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mm
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Sd
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Verify tu- (tdx-CA). Repeat using the calculated
value of tdx-CA until there is little difference between the calculated
values of tu and tdx-CA
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tu-(tdx-CA) =
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tu-(tdx1-CA) =
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tu-(tdx2-CA) =
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tu-(tdx3-CA) =
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t2a
= tdx-CA
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mm
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mm
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t2d =
t2 + CA
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mm
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UPPER-COURSE METHOD FOR HYDROSTATIC TEST CONDITIONS (t2a = ttx)
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CALCULATE THE RATIO R
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t₁ = t1use
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mm
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h1
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m
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mm
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r
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m
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mm
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R =
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h1
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(r x t1)⁰∙⁵
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R ≤
1.375
|
→
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R ≥
2.625
|
→
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1.375 < R < 2.625
|
→
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How R =
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→
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1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
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|
N (Lower)
|
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|
N (Course in Analysis)
|
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|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
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|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h1
|
|
mm
|
h1
|
|
mm
|
h1
|
|
mm
|
h1
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
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m
|
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Htank
|
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m
|
Htank
|
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m
|
Htank
|
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m
|
Htank
|
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m
|
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|
H = Htank - (N-1)*E (Lower)
|
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m
|
H (Lower)
|
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m
|
H (Lower)
|
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m
|
H (Lower)
|
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m
|
|
|
H = Htank - (N-1)*E (In Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
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G
|
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G
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|
|
G
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G
|
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|
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
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|
CA
|
|
mm
|
CA
|
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mm
|
CA
|
|
mm
|
CA
|
|
mm
|
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t1t
=
|
[
|
1.06 -
|
0.0696D
|
(
|
H
|
)
|
0,5
|
]
|
(
|
4.9HD
|
)
|
|
|
mm
|
t1t
|
|
mm
|
t1t
|
|
mm
|
t1t
|
|
mm
|
|
|
H
|
St
|
|
St
|
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tpt =
|
4.9D(H-0.3)
|
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mm
|
ttx
|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
|
|
St
|
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tL
= t1t
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|
|
mm
|
tL = t1t
|
|
mm
|
tL = t1t
|
|
mm
|
tL = t1t
|
|
mm
|
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tu
= tpt
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|
mm
|
tu = ttx
|
|
mm
|
tu = ttx₁
|
|
mm
|
tu = ttx2
|
|
mm
|
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K = tL/tu
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K
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K
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K
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
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C
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C
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X₁ = 0.61(rtu)⁰∙⁵+(320CH)
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X₁
|
|
|
X₁
|
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|
X₁
|
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X₂ = 1000CH
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X₂
|
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X₂
|
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X₂
|
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|
X₃ = 1.22(rtu)⁰∙⁵
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X₃
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X₃
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X₃
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X
|
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X
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X
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X
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ttx =
|
4.9D(H-X/1000)
|
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|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
ttx3
|
|
mm
|
|
|
St
|
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|
|
Verify tu-ttx. Repeat
using the calculated value of ttx until there is little difference between
the calculated values of tu and ttx
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tu-ttx =
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tu-ttx1 =
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tu-ttx2 =
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tu-ttx3 =
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t₂ₐ
= ttx
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mm
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mm
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t₂t = t₂
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mm
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|
THICKNESS OF THE SECOND COURSE
|
|
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|
|
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|
|
t2min is the higher
value between t2d & t2t
|
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|
|
mm
|
|
|
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|
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|
|
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|
|
t2use
|
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|
mm
|
(The additional
thickness will not be used for subsequent calculations)
|
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|
CALCULATING THE THICKNESS OF THE 3RD SHELL COURSE (N=3)
|
|
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|
|
UPPER-COURSE METHOD FOR DESIGN CONDITIONS (t3a = tdx-CA)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t2
= t2min-CA
|
|
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mm
|
|
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|
|
|
|
|
|
|
|
|
h2
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R =
|
h2
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t2)⁰∙⁵
|
|
|
|
|
|
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|
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|
|
|
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|
|
|
|
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|
|
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|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
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|
|
|
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|
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|
|
1.375 < R < 2.625
|
→
|
|
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|
|
|
|
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|
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|
How R =
|
|
→
|
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|
|
|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h2
|
|
mm
|
h2
|
|
mm
|
h2
|
|
mm
|
h2
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpd - CA=
|
4.9D(H-0.3)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx-CA
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t2d-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
tL = t2d-CA
|
|
mm
|
tL = t2d-CA
|
|
mm
|
tL = t2d-CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpd-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
tu = tdx-CA
|
|
mm
|
tu = tdx1-CA
|
|
mm
|
tu = tdx2-CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X₁ = 0.61(rtu)⁰∙⁵+(320CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 1000CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tdx - CA=
|
4.9D(H-X/1000)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
tdx3-CA
|
|
mm
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verify tu- (tdx-CA).
Repeat using the calculated value of tdx-CA until there is little difference
between the calculated values of tu and tdx-CA
|
|
|
|
|
|
|
|
|
|
tu-(tdx-CA) =
|
|
|
|
|
|
|
|
|
|
|
|
tu-(tdx1-CA) =
|
|
|
tu-(tdx2-CA) =
|
|
|
tu-(tdx3-CA) =
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t3a
= tdx-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t3d =
t3 + CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
UPPER-COURSE METHOD FOR HYDROSTATIC TEST CONDITIONS (t3a = ttx)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t2
= t2min
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
h2
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R =
|
h2
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t2)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
How R =
|
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h2
|
|
mm
|
h2
|
|
mm
|
h2
|
|
mm
|
h2
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t2t
= t2
|
|
|
|
|
|
|
|
|
|
|
mm
|
t2t = t2
|
|
mm
|
t2t = t2
|
|
mm
|
t2t = t2
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpt =
|
4.9D(H-0.3)
|
|
|
|
|
|
|
|
|
|
|
mm
|
ttx
|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t2t
|
|
|
|
|
|
|
|
|
|
|
mm
|
tL = t2t
|
|
mm
|
tL = t2t
|
|
mm
|
tL = t2t
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpt
|
|
|
|
|
|
|
|
|
|
|
mm
|
tu = ttx
|
|
mm
|
tu = ttx1
|
|
mm
|
tu = ttx2
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X₁ = 0.61(rtu)⁰∙⁵+(320CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 1000CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
ttx =
|
4.9D(H-X/1000)
|
|
|
|
|
|
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mm
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ttx1
|
|
mm
|
ttx2
|
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mm
|
ttx3
|
|
mm
|
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|
St
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Verify tu-ttx. Repeat
using the calculated value of ttx until there is little difference between
the calculated values of tu and ttx
|
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tu-ttx =
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tu-ttx1 =
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tu-ttx2 =
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tu-ttx3 =
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t3a = ttx
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mm
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mm
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t3t
= t3
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mm
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THICKNESS OF THE THIRD COURSE
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t3min is the higher
value between t3d & t3t
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mm
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t3use
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mm
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CALCULATING THE THICKNESS OF THE 4TH SHELL COURSE (N=4)
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UPPER-COURSE METHOD FOR DESIGN CONDITIONS (t4a = tdx-CA)
|
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|
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CALCULATE THE RATIO R
|
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|
t3
= t3min-CA
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mm
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h3
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m
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mm
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r
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m
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mm
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R =
|
h3
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(r x t3)⁰∙⁵
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R ≤
1.375
|
→
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R ≥
2.625
|
→
|
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|
1.375 < R < 2.625
|
→
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How R =
|
|
→
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|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
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|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h3
|
|
mm
|
h3
|
|
mm
|
h3
|
|
mm
|
h3
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
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|
|
tpd - CA=
|
4.9D(H-0.3)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx-CA
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
|
|
Sd
|
|
|
|
|
|
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|
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|
|
tL
= t3d-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
tL = t3d-CA
|
|
mm
|
tL = t3d-CA
|
|
mm
|
tL = t3d-CA
|
|
mm
|
|
|
|
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|
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|
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|
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|
|
tu
= tpd-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
tu = tdx-CA
|
|
mm
|
tu = tdx1-CA
|
|
mm
|
tu = tdx2-CA
|
|
mm
|
|
|
|
|
|
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|
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|
|
K = tL/tu
|
|
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|
K
|
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|
K
|
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|
K
|
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|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
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|
C
|
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|
C
|
|
|
C
|
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|
|
X₁ = 0.61(rtu)⁰∙⁵+(320CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 1000CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
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|
|
X
|
|
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|
|
X
|
|
|
X
|
|
|
X
|
|
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|
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|
|
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|
|
|
|
|
tdx - CA=
|
4.9D(H-X/1000)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
tdx3-CA
|
|
mm
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verify tu- (tdx-CA).
Repeat using the calculated value of tdx-CA until there is little difference
between the calculated values of tu and tdx-CA
|
|
|
|
|
|
|
|
|
|
tu-(tdx-CA) =
|
|
|
|
|
|
|
|
|
|
|
tu-(tdx1-CA) =
|
|
|
tu-(tdx2-CA) =
|
|
|
tu-(tdx3-CA) =
|
|
|
|
|
|
|
|
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|
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|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
t4a
= tdx-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
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|
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|
|
|
mm
|
|
|
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|
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|
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|
|
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|
|
|
|
|
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|
|
|
|
|
|
|
t4d
= t4 + CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
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|
|
|
|
|
|
|
|
|
|
|
|
UPPER-COURSE METHOD FOR HYDROSTATIC TEST CONDITIONS (t4a = ttx)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t3
= t3min
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
h3
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R =
|
h3
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t3)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
How R =
|
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h3
|
|
mm
|
h3
|
|
mm
|
h3
|
|
mm
|
h3
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t3t
= t3
|
|
|
|
|
|
|
|
|
|
|
mm
|
t3t = t3
|
|
mm
|
t3t = t3
|
|
mm
|
t3t = t3
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpt =
|
4.9D(H-0.3)
|
|
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mm
|
ttx
|
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mm
|
ttx1
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mm
|
ttx2
|
|
mm
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St
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tL
= t3t
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mm
|
tL = t3t
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|
mm
|
tL = t3t
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|
mm
|
tL = t3t
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mm
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tu
= tpt
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mm
|
tu = ttx
|
|
mm
|
tu = ttx1
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mm
|
tu = ttx2
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mm
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K = tL/tu
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K
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K
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K
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
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C
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C
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X₁ = 0.61(rtu)⁰∙⁵+(320CH)
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X₁
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X₁
|
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X₁
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X₂ = 1000CH
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X₂
|
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X₂
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X₂
|
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|
X₃ = 1.22(rtu)⁰∙⁵
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X₃
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X₃
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X₃
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X
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X
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X
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|
X
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|
ttx =
|
4.9D(H-X/1000)
|
|
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|
|
|
|
|
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|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
ttx3
|
|
mm
|
|
|
St
|
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|
|
Verify tu-ttx. Repeat
using the calculated value of ttx until there is little difference between
the calculated values of tu and ttx
|
|
|
|
|
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|
|
tu-ttx =
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|
tu-ttx1 =
|
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|
tu-ttx2 =
|
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|
tu-ttx3 =
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t4a
= ttx
|
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mm
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mm
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|
t4t
= t4
|
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|
mm
|
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|
|
THICKNESS OF THE FOURTH COURSE
|
|
|
|
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|
|
|
t4min is the higher
value between t4d & t4t
|
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|
mm
|
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|
t4use
|
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|
mm
|
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|
|
|
|
|
CALCULATING THE THICKNESS OF THE 5TH SHELL COURSE (N=5)
|
|
|
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|
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|
|
UPPER-COURSE METHOD FOR DESIGN CONDITIONS (t5a = tdx-CA)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t4
= t4min-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
h4
|
|
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|
|
|
|
|
|
|
|
m
|
|
mm
|
|
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|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
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|
|
R =
|
h4
|
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|
|
|
|
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|
|
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|
|
|
|
|
|
|
|
|
|
|
(r x t4)⁰∙⁵
|
|
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|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
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|
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|
|
How R =
|
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h4
|
|
mm
|
h4
|
|
mm
|
h4
|
|
mm
|
h4
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpd - CA=
|
4.9D(H-0.3)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx-CA
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t4d-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
tL = t4d-CA
|
|
mm
|
tL = t4d-CA
|
|
mm
|
tL = t4d-CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpd-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
tu = tdx-CA
|
|
mm
|
tu = tdx1-CA
|
|
mm
|
tu = tdx2-CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X₁ = 0.61(rtu)⁰∙⁵+(320CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 1000CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tdx - CA=
|
4.9D(H-X/1000)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
tdx3-CA
|
|
mm
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verify tu- (tdx-CA).
Repeat using the calculated value of tdx-CA until there is little difference
between the calculated values of tu and tdx-CA
|
|
|
|
|
|
|
|
|
|
tu-(tdx-CA) =
|
|
|
|
|
|
|
|
|
|
|
|
tu-(tdx1-CA) =
|
|
|
tu-(tdx2-CA) =
|
|
|
tu-(tdx3-CA) =
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t5a
= tdx-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t5d
= t5 + CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
UPPER-COURSE METHOD FOR HYDROSTATIC TEST CONDITIONS (t5a = ttx)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t4
= t4min
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
h4
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R =
|
h4
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t4)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
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How R =
|
|
→
|
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|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h4
|
|
mm
|
h4
|
|
mm
|
h4
|
|
mm
|
h4
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
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|
t4t
= t4
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mm
|
t4t = t4
|
|
mm
|
t4t = t4
|
|
mm
|
t4t = t4
|
|
mm
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|
tpt =
|
4.9D(H-0.3)
|
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|
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|
mm
|
ttx
|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
|
|
St
|
|
|
|
|
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|
tL
= t4t
|
|
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|
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|
|
|
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|
|
mm
|
tL = t4t
|
|
mm
|
tL = t4t
|
|
mm
|
tL = t4t
|
|
mm
|
|
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|
tu
= tpt
|
|
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|
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|
|
mm
|
tu = ttx
|
|
mm
|
tu = ttx1
|
|
mm
|
tu = ttx2
|
|
mm
|
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|
K = tL/tu
|
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|
K
|
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|
K
|
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|
K
|
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|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
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|
C
|
|
|
C
|
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|
C
|
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|
|
X₁ = 0.61(rtu)⁰∙⁵+(320CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 1000CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
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|
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|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
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|
|
X
|
|
|
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|
|
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|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
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|
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|
|
|
|
|
ttx =
|
4.9D(H-X/1000)
|
|
|
|
|
|
|
|
|
|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
ttx3
|
|
mm
|
|
|
St
|
|
|
|
|
|
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|
|
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|
|
|
|
|
|
|
|
|
|
|
Verify tu-ttx. Repeat
using the calculated value of ttx until there is little difference between
the calculated values of tu and ttx
|
|
|
|
|
|
|
|
|
tu-ttx =
|
|
|
|
|
|
|
|
|
|
|
|
tu-ttx1 =
|
|
|
tu-ttx2 =
|
|
|
tu-ttx3 =
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
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|
|
|
|
|
|
|
t5a
= ttx
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
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|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t5t
= t5
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
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|
|
|
|
|
|
|
|
|
|
THICKNESS OF THE FIFTH COURSE
|
|
|
|
|
|
|
|
t5min is the higher
value between t5d & t5t
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
t5use
|
|
|
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
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|
|
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|
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|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
CALCULATING THE THICKNESS OF THE 6TH SHELL COURSE (N=6)
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
UPPER-COURSE METHOD FOR DESIGN CONDITIONS (t6a = tdx-CA)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t5
= t5min-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
h5
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R =
|
h5
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t5)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
How R =
|
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h5
|
|
mm
|
h5
|
|
mm
|
h5
|
|
mm
|
h5
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpd - CA=
|
4.9D(H-0.3)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx-CA
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t5d-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
tL = t5d-CA
|
|
mm
|
tL = t5d-CA
|
|
mm
|
tL = t5d-CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpd-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
tu = tdx-CA
|
|
mm
|
tu = tdx1-CA
|
|
mm
|
tu = tdx2-CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X₁ = 0.61(rtu)⁰∙⁵+(320CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 1000CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tdx - CA=
|
4.9D(H-X/1000)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
tdx3-CA
|
|
mm
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verify tu- (tdx-CA).
Repeat using the calculated value of tdx-CA until there is little difference
between the calculated values of tu and tdx-CA
|
|
|
|
|
|
|
|
|
|
tu-(tdx-CA) =
|
|
|
|
|
|
|
|
|
|
|
|
tu-(tdx1-CA) =
|
|
|
tu-(tdx2-CA) =
|
|
|
tu-(tdx3-CA) =
|
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t6a
= tdx-CA
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mm
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mm
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t6d
= t6 + CA
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mm
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UPPER-COURSE METHOD FOR HYDROSTATIC TEST CONDITIONS (t6a = ttx)
|
|
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CALCULATE THE RATIO R
|
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t5
= t5min
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mm
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h5
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m
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mm
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r
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m
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mm
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R =
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h5
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(r x t5)⁰∙⁵
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R ≤
1.375
|
→
|
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R ≥
2.625
|
→
|
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1.375 < R < 2.625
|
→
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How R =
|
|
→
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|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h5
|
|
mm
|
h5
|
|
mm
|
h5
|
|
mm
|
h5
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
|
|
|
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|
|
t5t
= t5
|
|
|
|
|
|
|
|
|
|
|
mm
|
t5t = t5
|
|
mm
|
t5t = t5
|
|
mm
|
t5t = t5
|
|
mm
|
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|
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|
|
tpt =
|
4.9D(H-0.3)
|
|
|
|
|
|
|
|
|
|
|
mm
|
ttx
|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
|
|
St
|
|
|
|
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|
|
|
|
|
|
tL
= t5t
|
|
|
|
|
|
|
|
|
|
|
mm
|
tL = t5t
|
|
mm
|
tL = t5t
|
|
mm
|
tL = t5t
|
|
mm
|
|
|
|
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|
|
tu
= tpt
|
|
|
|
|
|
|
|
|
|
|
mm
|
tu = ttx
|
|
mm
|
tu = ttx1
|
|
mm
|
tu = ttx2
|
|
mm
|
|
|
|
|
|
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|
|
|
|
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|
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|
|
|
K = tL/tu
|
|
|
|
|
|
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|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
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|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
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|
|
C
|
|
|
C
|
|
|
C
|
|
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|
|
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|
|
|
X₁ = 0.61(rtu)⁰∙⁵+(320CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 1000CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
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|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
|
|
|
ttx =
|
4.9D(H-X/1000)
|
|
|
|
|
|
|
|
|
|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
ttx3
|
|
mm
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verify tu-ttx. Repeat
using the calculated value of ttx until there is little difference between
the calculated values of tu and ttx
|
|
|
|
|
|
|
|
|
tu-ttx =
|
|
|
|
|
|
|
|
|
|
|
|
tu-ttx1 =
|
|
|
tu-ttx2 =
|
|
|
tu-ttx3 =
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t6a
= ttx
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
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|
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|
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|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t6t
= t6
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
THICKNESS OF THE SIXTH COURSE
|
|
|
|
|
|
|
|
t6min is the higher
value between t6d & t6t
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
t6use
|
|
|
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
CALCULATING THE THICKNESS OF THE 7TH SHELL COURSE (N=7)
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
UPPER-COURSE METHOD FOR DESIGN CONDITIONS (t7a = tdx-CA)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t6
= t6min-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
h6
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R =
|
h6
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t6)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
How R =
|
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h6
|
|
mm
|
h6
|
|
mm
|
h6
|
|
mm
|
h6
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpd - CA=
|
4.9D(H-0.3)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx-CA
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t6d-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
tL = t6d-CA
|
|
mm
|
tL = t6d-CA
|
|
mm
|
tL = t6d-CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
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tu
= tpd-CA
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|
|
mm
|
tu = tdx-CA
|
|
mm
|
tu = tdx1-CA
|
|
mm
|
tu = tdx2-CA
|
|
mm
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K = tL/tu
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K
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K
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K
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
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C
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C
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X₁ = 0.61(rtu)⁰∙⁵+(320CH)
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|
X₁
|
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X₁
|
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X₁
|
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X₂ = 1000CH
|
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|
X₂
|
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|
X₂
|
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|
X₂
|
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|
|
X₃ = 1.22(rtu)⁰∙⁵
|
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|
X₃
|
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|
X₃
|
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|
X₃
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X
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X
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X
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X
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|
|
tdx - CA=
|
4.9D(H-X/1000)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
tdx3-CA
|
|
mm
|
|
|
Sd
|
|
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|
|
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|
|
|
|
|
|
Verify tu- (tdx-CA).
Repeat using the calculated value of tdx-CA until there is little difference
between the calculated values of tu and tdx-CA
|
|
|
|
|
|
|
|
|
|
tu-(tdx-CA) =
|
|
|
|
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|
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|
|
|
|
tu-(tdx1-CA) =
|
|
|
tu-(tdx2-CA) =
|
|
|
tu-(tdx3-CA) =
|
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|
t7a
= tdx-CA
|
|
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|
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|
mm
|
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mm
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|
|
t7d
= t7 + CA
|
|
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|
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|
mm
|
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|
|
UPPER-COURSE METHOD FOR HYDROSTATIC TEST CONDITIONS (t7a = ttx)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t6
= t6min
|
|
|
|
|
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|
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|
mm
|
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|
|
|
|
|
|
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|
|
h6
|
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|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
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|
|
|
m
|
|
mm
|
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|
R =
|
h6
|
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|
|
|
|
(r x t6)⁰∙⁵
|
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|
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|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
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|
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|
|
|
|
|
|
How R =
|
|
→
|
|
|
|
|
|
|
|
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|
|
|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h6
|
|
mm
|
h6
|
|
mm
|
h6
|
|
mm
|
h6
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t6t
= t6
|
|
|
|
|
|
|
|
|
|
|
mm
|
t6t = t6
|
|
mm
|
t6t = t6
|
|
mm
|
t6t = t6
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpt =
|
4.9D(H-0.3)
|
|
|
|
|
|
|
|
|
|
|
mm
|
ttx
|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t6t
|
|
|
|
|
|
|
|
|
|
|
mm
|
tL = t6t
|
|
mm
|
tL = t6t
|
|
mm
|
tL = t6t
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpt
|
|
|
|
|
|
|
|
|
|
|
mm
|
tu = ttx
|
|
mm
|
tu = ttx1
|
|
mm
|
tu = ttx2
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X₁ = 0.61(rtu)⁰∙⁵+(320CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 1000CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
ttx =
|
4.9D(H-X/1000)
|
|
|
|
|
|
|
|
|
|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
ttx3
|
|
mm
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verify tu-ttx. Repeat
using the calculated value of ttx until there is little difference between
the calculated values of tu and ttx
|
|
|
|
|
|
|
|
|
tu-ttx =
|
|
|
|
|
|
|
|
|
|
|
|
tu-ttx1 =
|
|
|
tu-ttx2 =
|
|
|
tu-ttx3 =
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t7a
= ttx
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t7t
= t7
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
THICKNESS OF THE SEVENTH COURSE
|
|
|
|
|
|
|
|
t7min is the higher
value between t7d & t7t
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
t7use
|
|
|
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
CALCULATING THE THICKNESS OF THE 8TH SHELL COURSE (N=8)
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
UPPER-COURSE METHOD FOR DESIGN CONDITIONS (t8a = tdx-CA)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t7
= t7min-CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
h7
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R =
|
h7
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t7)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
How R =
|
|
→
|
|
|
|
|
|
|
|
|
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1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
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N (Lower)
|
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|
|
N (Course in Analysis)
|
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|
N (Analysis)
|
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|
N (Analysis)
|
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|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h7
|
|
mm
|
h7
|
|
mm
|
h7
|
|
mm
|
h7
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
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|
G
|
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|
G
|
|
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|
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
Sd
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
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|
tpd - CA=
|
4.9D(H-0.3)G
|
|
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|
|
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|
mm
|
tdx-CA
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
|
|
Sd
|
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tL
= t7d-CA
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|
mm
|
tL = t7d-CA
|
|
mm
|
tL = t7d-CA
|
|
mm
|
tL = t7d-CA
|
|
mm
|
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tu
= tpd-CA
|
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|
|
|
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|
|
|
|
|
mm
|
tu = tdx-CA
|
|
mm
|
tu = tdx1-CA
|
|
mm
|
tu = tdx2-CA
|
|
mm
|
|
|
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K = tL/tu
|
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K
|
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K
|
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|
K
|
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
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C
|
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C
|
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C
|
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X₁ = 0.61(rtu)⁰∙⁵+(320CH)
|
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|
X₁
|
|
|
X₁
|
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|
X₁
|
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|
|
X₂ = 1000CH
|
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|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
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|
|
X₃ = 1.22(rtu)⁰∙⁵
|
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|
X₃
|
|
|
X₃
|
|
|
X₃
|
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X
|
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X
|
|
|
X
|
|
|
X
|
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|
tdx - CA=
|
4.9D(H-X/1000)G
|
|
|
|
|
|
|
|
|
|
|
mm
|
tdx1-CA
|
|
mm
|
tdx2-CA
|
|
mm
|
tdx3-CA
|
|
mm
|
|
|
Sd
|
|
|
|
|
|
|
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|
|
|
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|
|
Verify tu- (tdx-CA).
Repeat using the calculated value of tdx-CA until there is little difference
between the calculated values of tu and tdx-CA
|
|
|
|
|
|
|
|
|
|
tu-(tdx-CA) =
|
|
|
|
|
|
|
|
|
|
|
|
tu-(tdx1-CA) =
|
|
|
tu-(tdx2-CA) =
|
|
|
tu-(tdx3-CA) =
|
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|
|
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|
t8a
= tdx-CA
|
|
|
|
|
|
|
|
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|
|
mm
|
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|
mm
|
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|
|
t8d
= t8 + CA
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
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|
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|
|
UPPER-COURSE METHOD FOR HYDROSTATIC TEST CONDITIONS (t8a = ttx)
|
|
|
|
|
|
|
|
CALCULATE THE RATIO R
|
|
|
|
|
|
|
|
t7
= t7min
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
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|
|
h7
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
m
|
|
mm
|
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|
|
R =
|
h7
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t7)⁰∙⁵
|
|
|
|
|
|
|
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|
|
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|
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|
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|
|
|
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|
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|
|
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|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
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|
|
|
How R =
|
|
→
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
1st Iteration
|
|
2nd Iteration
|
|
3th Iteration
|
|
|
|
N (Lower Course)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
N (Lower)
|
|
|
|
|
N (Course in Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
N (Analysis)
|
|
|
|
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
Dtank
|
|
m
|
|
|
h7
|
|
mm
|
h7
|
|
mm
|
h7
|
|
mm
|
h7
|
|
mm
|
|
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
r
|
|
mm
|
|
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
E
|
|
m
|
|
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
Htank
|
|
m
|
|
|
H = Htank - (N-1)*E
(Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
H (Lower)
|
|
m
|
|
|
H = Htank - (N-1)*E (In
Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
H (Analysis)
|
|
m
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
St
|
|
MPa
|
|
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
CA
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t7t
= t7
|
|
|
|
|
|
|
|
|
|
|
mm
|
t7t = t7
|
|
mm
|
t7t = t7
|
|
mm
|
t7t = t7
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpt =
|
4.9D(H-0.3)
|
|
|
|
|
|
|
|
|
|
|
mm
|
ttx
|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t7t
|
|
|
|
|
|
|
|
|
|
|
mm
|
tL = t7t
|
|
mm
|
tL = t7t
|
|
mm
|
tL = t7t
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpt
|
|
|
|
|
|
|
|
|
|
|
mm
|
tu = ttx
|
|
mm
|
tu = ttx1
|
|
mm
|
tu = ttx2
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X₁ = 0.61(rtu)⁰∙⁵+(320CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 1000CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
ttx =
|
4.9D(H-X/1000)
|
|
|
|
|
|
|
|
|
|
|
mm
|
ttx1
|
|
mm
|
ttx2
|
|
mm
|
ttx3
|
|
mm
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verify tu-ttx. Repeat
using the calculated value of ttx until there is little difference between
the calculated values of tu and ttx
|
|
|
|
|
|
|
|
|
tu-ttx =
|
|
|
|
|
|
|
|
|
|
|
|
tu-ttx1 =
|
|
|
tu-ttx2 =
|
|
|
tu-ttx3 =
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t8a
= ttx
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t8t
= t8
|
|
|
|
|
|
|
|
|
|
|
mm
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
THICKNESS OF THE EIGHTH COURSE
|
|
|
|
|
|
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t8min is the higher
value between t8d & t8t
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mm
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t8use
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mm
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